Question

Fill in the blank question.

A rolling ball has an initial velocity of 1.6 m/s.


a. If the ball has a constant acceleration of 0.33 m/s² in the same direction as its movement, its speed after 3.6 s is

.......m/s.


b. After 3.6 s, the ball has traveled a distance of

..........m.
fill in the dots

Answer 1

Explanation:

u = 1.6  

a.

a = 0.33   t = 3.6  Find v ; Using v = u + at

v = 1.6 + (0.33)(3.6) = 2.788

b.

Find s ; UsIng $v^{2}= u^{2} + 2as$

$(2.788)^{2}= (1.6)^{2} + 2(0.33)(s)$

7.772944 = 2.56 + 0.66s

5.212944 = 0.66s

s = 7.8984

please give me a brainliest answer

Answer 2

Answer:

A.

Explanation:

If the ball has a constant accelration of 0.33  m/s3 the speed would be

3.6s.

thats how it is A.