Step-by-step explanation:
(x + 8)(x - 1) > 0
It has 2 cases;
1. x + 8 > 0 ; x > -8 and x - 1 > 0 ; x > 1
2. x + 8 < 0 ; x < -8 and x - 1 < 0 ; x < 1
Find the intersection ; x ∈ < 1 , +∞ > and x ∈ < -∞ , -8 >
So x ∈ < -∞ , -8 > ∪ < 1 , +∞ >
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