Answer:
Step-by-step explanation:
Remember the format for a straight line: y=mx+b, where m is the slope and b is the y-intercept (the value of y when x = 0).
The slope of a line that is perpendicular to y= 4/3x-2 will have a slope that is the negative inverse of this slope (4/3). That would make it -(3/4). A perpendicular line will take this form:
y = -(3/4)x + b
Any value for b will not alter the fact that this line will be perpendicular, only move it around. In this case we want the new line, u, to go through point (-2,2). So let's find the value of b that will make that happen.
Enter the point (-2,2) into the equation y = -(4/3)x + b:
y = -(3/4)x + b
2 = -(3/4)*(-2) + b
2 = (6/4) + b
b = (8/4)-(6/4)
b = (2/4) or (1/2)
The equation for a line perpendicular to y= 4/3x-2 is y = -(3/4)x + (1/2).
