The total number of ways in which the 3 people line up for the 3 cashiers is 36 ways.
First, we consider the number of ways in which we can arrange the 3 cashiers. Since order matters, we use permutation. So, we have ³P₃ ways of arranging the 3 cashiers. ³P₃ = 3 × 2 × 1 = 6 ways.
Also, the number of ways we can arrange the 3 people to line up since order matters is ³P₃ = 3 × 2 × 1 = 6 ways.
So, the total number of ways in which we can arrange both the 3 cashiers and the 3 people in a line is ³P₃ × ³P₃ = 6 × 6 = 36 ways.
The total number of ways in which the 3 people line up for the 3 cashiers is 36 ways.
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Answer:
60 ways
Step-by-step explanation:
So, sadly there is no real algorithm that I could find for this so I just went ahead and listed all the ways that the people can be organized
3,0,0
0,3,0
0,0,3
2,1,0
2,0,1
1,2,0
1,0,2
0,2,1
0,1,2
1,1,1
So, we have 10 ways to organize them. But we need to remember that there are also 6 ways to randomly organize 3 people. So, 10x6 is 60
