Question

A wheel is formed from a hoop of mass 4.3 kgand three equally spaced spokes, each of mass0.15 kg. The hoop’s radius is the length0.67 m of each spoke.

Answer 1

The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

The given parameters;

• mass of the hoop, M = 43. kg
• mass of each spoke, m = 0.15 kg
• radius of the hoop, r = 0.67 m

The moment of inertial of the wheel is calculated as follows;

$I = I_{hoop} + 3I_{spoke}\\\\I = MR^2\ + \ 3(\frac{1}{3} mL^2)\\\\I = (4.3 \times 0.67^2) \ + \ (0.15 \times 0.67^2)\\\\I = 2.0 \ kgm^2$

Thus, the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

"Your question is not complete, it seems to be missing the following information";

find the moment of inertial of the wheel about an axis through its center and perpendicular to the plane of the wheel.

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