Question

Find the zeros of f (x) = 8x^2 - 1.
The zeros are x = ___and x___​

Answer 1

Answer:

x=$\sqrt{2}$/4 and x=-$\sqrt{2}$/4

Step-by-step explanation:

One method of solving is using the Quadratic Formula: -b ±$\sqrt{b^{2}-4ac }$/2a, with a=8, b=0, and c=-1.

After plugging these values in you get -0±$\sqrt{0^2-(4*8*-1)}$/2*8

After simplifying you get ±$\sqrt{32}$/16

Because 32 is 2^5, you can simplify it to 4$\sqrt{2}$, which makes the equation ±4$\sqrt{2}$/16, or ±$\sqrt{2}$/4.