Question

For simplicity, rate earthquake intensities into low (L), medium (M), and high (H). The likelihoods of liquefaction associated with earthquakes of these intensities are, respectively, 0.05, 0.20, and 0.90. Assume that the relative frequencies of occurrence of earthquakes of these intensities are, respectively, 1, 0.1, and 0.01 per year. (a) What is the probability that the next earthquake is of low intensity

Answer 1

Using the concept of probability, it is found that there is a 0.9009 = 90.09% probability that the next earthquake is of low intensity.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

• The sum of the frequencies is 1 + 0.1 + 0.01 = 1.11.
• Of those, 1.0 is relative to low intensity earthquakes, thus:

$p = \frac{1}{1.11} = 0.9099$

0.9009 = 90.09% probability that the next earthquake is of low intensity.

A similar problem is given at https://brainly.com/question/24658381