Question

Q1. A 130 N horizontal force keeps a 30 kg chair moving at a constant velocity. Find the
coefficient of kinetic friction between the chair and the floor.

Answer 1

The coefficient of kinetic friction between the chair and the floor is 0.442.

The given parameters;

• horizontal force on the chair, F = 130 N
• mass of the chair, m = 30 kg

The normal force on the chair is calculated as follows;

Fₙ = mg

Fₙ = 30 x 9.8 = 294 N

The frictional force between the chair and the floor is calculated as follows;

Fk = μFₙ

The net force on the chair is calculated as follows;

$\Sigma F_x = 0\\\\F- \mu_k F_n = 0\\\\130 - \mu_k (294) = 0\\\\\mu_k = \frac{130}{294} \\\\\mu_k = 0.442$

Thus, the coefficient of kinetic friction between the chair and the floor is 0.442.

Learn more here:https://brainly.com/question/20241845