Question

what is the energy of light for a single photon that has a wavelength of 347 nm?

Answer 1

The energy of light for a single photon that has a wavelength of 347 nm is 5.698 × 10-¹⁹ J

HOW TO CALCULATE ENERGY:

• The energy of a photon of light can be calculated by using the following formula:

E = hf

Where;

1. E = energy of photon (J)
2. h = Planck's constant (6.626 × 10-³⁴J/s)
3. f = frequency (Hz)

• However, the frequency must first be calculated using the formula as follows:

λ = v/f

Where;

1. λ = wavelength
2. v = speed of light (3 × 10⁸m/s)
3. f = frequency

• f = v ÷ λ

• f = 3 × 10⁸ ÷ 347 × 10-⁹

• f = 3/347 × 10⁸+⁹

• f = 0.0086 × 10¹⁷ Hz

• f = 8.6 × 10¹⁴ Hz

• E = 6.626 × 10-³⁴ × 8.6 × 10¹⁴

• E = 56.98 × 10-²⁰

• E = 5.698 × 10-¹⁹ J

• Therefore, the energy of light for a single photon that has a wavelength of 347 nm is 5.698 × 10-¹⁹ J.

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