Question

An arrow is launched upward with a velocity of 160 feet per second from top of a 50 foot stage. What is the maximum height attained by the arrow

Answer 1

The maximum height attained by the arrow is 4000 feet

Since the arrow is launched upward, the angle between the arrow and the horizontal floor is 90 degrees

The formula for calculating the maximum height attained is expressed as:

$H=\frac{u^2sin^2\theta}{2g}$

Given the following parameters

u = 160ft/s

g = 32ft/s²

$\theta=90^0$

Substitute the given parameters into the formula as shown:

$H=\frac{160^2sin^2(90)}{2(32)}\\H=\frac{25600}{64}\\H= 4000feet$

Hence the maximum height attained by the arrow is 4000 feet

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