Question

Three consecutive integers have a sum of 45. Find the integers.

Answer 1

Answer:

14,15,16

Step-by-step explanation:

Call n the first integer so you get:

n+(n+1)+(n+2)=45

3n+3=45

3n=42

n=14

The integers are:

14,15,16

Answer 2

Answer:

14,15,16

Step-by-step explanation:

Let the integers be x, (x+1),(x+2)

So,

x+(x+1)+(x+2)=45

x+x+1+x+2=45

3x+3=45

3x=45-3

x= 42/3

x=14

Now put the value.

• x= 14
• (x+1)= 14+1= 15
• (x+2)=14+2= 16

Now, Add these integers

you'll get

14+15+16=45