Question

write the equation
it has a slope of -8/3 and passes through (0,8)

Answer 1

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The equation of line having slope of -8/3 and passes through (0,8) is ~

• $y = - \dfrac{8}{3} x + 8$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Slope of given line is ~

• $- \dfrac{8}{3}$

And coordinates of a point on the given line is :

• $(0,8)$

now, let's use the point - slope form of line to find the equation of the given line ~

that is ~

• $y - y1 = m(x - x1)$

• $y - 8 = - \dfrac{ 8}{3} (x - 0)$

• $y - 8 = - \dfrac{8}{3} (x)$

• $y - 8 = - \dfrac{8}{3} x$

• $y = - \dfrac{8}{3} x + 8$