Question

A 1.35 kg block is pulled across a
flat, frictionless floor with a 3.07 N
force at 32.0° above horizontal.
What is the acceleration of the block?

Answer 1

Answer:

F=ma

3.07=1.35(a)

3.07/1.35 = a

a=2.27m/s^2

Explanation:

Since the question gives us both the force and mass of the object we can use the f= ma equation and just plug in both the force and mass and just solve for acceleration. I believe the degree listed in the question is just there to throw you off.