Question

a
A 49.8 mL sample of gas in a cylinder is warmed
from 18°C to 83 °C.
what is it’s volume at the final temperature? (Assume constant pressure)

Answer 1

• V_1=49.8mL
• T_1=18°C=291K
• T_2=83°C=356K

Using Charles law

$\\ \sf\longmapsto V_1T_2=V_2T_1$

$\\ \sf\longmapsto V_2=V_1T_2\div T_1$

$\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}$

$\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}$

$\\ \sf\longmapsto V_2=60.9mL$