Question

Help for questions 13, and 15

Answer 1

Answer:

Below

Explanation:

13. Given : Vx = 61.5 m/s , dx = 291 m , dy = ?

First we need to find the time of flight for this projectile :

     dx = vx (t)

     291 = 61.5(t)

     4.7317 s = t

Now we can find dy with this equation :

     $dy = \frac{t^2(g)}{2}$

     $dy = \frac{4.7317^2(9.8)}{2}$

     $dy = 109.706$

We need to round this to 3 sig figs :

     $dy = 110 m$

15. I just realized I already solved for that above! It is 4.73 seconds!

Hope this helps! Best of luck <3