Answer:
y=-2x²+4x+9
Step-by-step explanation:
Firstly, we need to know the general formula of a quadratic, given by:
[tex]y=ax^2+bx+c[/tex]
We need to form three equations with the coordinates we were given, and then we will find each variable.
The three coordinates given,
(4,-7) (-5-61) (-3, -21)
We can begin using (4,-7)
So, plugging those values in, we get
-7= a(4²)+b(4)+c
-7=16a+4b+c
Let's remember this equation and come back to it later.
Secondly, we will use (-5,-61)
-61= a(-5²)+b(-5)+c
-61=25a-5b+c
Again, let's remember this and move onto our last one.
(-3, -21)
-21=a(-3²)+b(-3)+c
-21=9a-3b+c
Now, we have three equations with three variables, so we can use the system of equations to solve for each one.
-7=16a+4b+c
-61=25a-5b+c
-21=9a-3b+c
By solving the system of equations, we eventually get
a=-2, b=4 and c=9
Thus,
y=-2x²+4x+9