The picture I took is what I need help with.

Answer:
4th option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 6, 0 ) and (x₂, y₂ ) = (0, - 9) ← 2 points on the line
m = [tex]\frac{-9-0}{0-(-6)}[/tex] = [tex]\frac{-9}{0+6}[/tex] = [tex]\frac{-9}{6}[/tex] = - [tex]\frac{3}{2}[/tex]
The line crosses the y- axis at (0, - 9 ) ⇒ c = - 9
y = - [tex]\frac{3}{2}[/tex] x - 9 ← in slope- intercept form
Multiply through by 2 to clear the fraction
2y = - 3x - 18 ( add 3x to both sides )
3x + 2y = - 18 ← in standard form