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adding 3 to some number , then multiplying the result by 7 give 28 what was the original number?
pls answer me now​

Respuesta :

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The required number is :

  • [tex]1[/tex]

[tex] \large \boxed{ \mathfrak{Explanation}}[/tex]

Let the number be represented as " x "

from the given statement we can infer that :

  • [tex]7(x + 3) = 28[/tex]

So, let's find the value of " x " from the given equation ~

  • [tex]x + 3 = 28 \div 7[/tex]

  • [tex]x + 3 = 4[/tex]

  • [tex]x = 4 - 3[/tex]

  • [tex]x = 1[/tex]

Answer:

Let the required original number be " x "

According to the given problem,

[tex]7(x + 3) = 28 \\ (x + 3) = \frac{28}{7} \\ (x + 3) = 4 \\ x =(4 - 3) \\ \boxed{x = 1}[/tex]

  • Hence, the original number is 1.
  • 1 is the right answer.
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