Question

Find the 16th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 1.

Answer 1

Answer:

136

Step-by-step explanation:

Common difference of 9 means that each term is 9 apart from each other:

1 + 9 = 10 + 9 = 19 + 9 = 28 ...

We can then find the nth term

The difference is 9 → 9n

The 0th term is 1 - 9 = -8

nth term = 9n - 8

Finally plug in (substitute) 16 for n

9(16) - 8 = 144 - 8 = 136

The 16th term is 136

Answer 2

Question : -

Find the 16th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 1.

Given : -

• common difference ( d ) = 9

• first term ( a ) = 1

To Find : -

We have to find the 16th term of Arithmetic Progression or sequence .

Concept : -

Concept of this question belongs to arithmetic progression ( sequence ) where we can find the values of a , d , nth term by using nth term formula .

So Starting the Solution : -

We know that 16th term of a.p. is ,

• a + ( 16 - 1 ) d

• a + 15 d --------- ( 1 )

Here value of ,

• a = 1

• d = 9

Substituting, value of a and d in equation 1 :

• 1 + 15 ( 9 )

• 1 + 135

• 136

Therefore , 16th term of the given arithmetic progression is 136 .

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