Question

I need help with Special Right Triangles. Thanks :)

Answer 1

Answer: c

Step-by-step explanation:

sin(45) =  $\frac{12}{AB}$

sin(45) = $\frac{\sqrt{2} }{2}$

so $\frac{\sqrt{2} }{2} =\frac{12}{AB}$

$AB = \frac{24}{\sqrt{2} }$

$AB = (\frac{24}{\sqrt{2} }) (\frac{\sqrt{2} }{\sqrt2} } )$

$AB = \frac{24\sqrt{2} }{2}$

$AB= 12\sqrt{2}$

Please give me a brainliest answer

Answer 2

$\\ \sf\longmapsto cos45=\dfrac{CB}{AB}$

$\\ \sf\longmapsto \dfrac{1}{\sqrt{2}}=\dfrac{12}{AB}$

$\\ \sf\longmapsto AB=12\sqrt{2}$