Question

1² x 1/4m² x (-6)ml find the product
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Answer 1

$\\ \sf\longmapsto 1^2\times \dfrac{1}{4}m^2$

$\\ \sf\longmapsto \dfrac{1}{4}m^2$

Now

$\\ \sf\longmapsto \dfrac{1}{4}m^2\times -6m$

$\\ \sf\longmapsto \dfrac{-6}{4}m^3$

$\\ \sf\longmapsto \dfrac{-3}{2}m^3$