Question

f(x)=x2+6x+7 and f(x)=x2−4x+11
what is the vertex form of them both?

Answer 1

f(x) = x$Number 1: f(x) = x^{2} + 6x + 7 f(x) = (x^{2} + 6x) + 7 f(x) = ( x^{2} + 6x + 9) +7 - (9) f(x) = (x + 3)^{2} - 2 Number 2 f(x) = x^{2} - 4x +11 f(x) = ( x^{2} -4x) +11 f(x) = (x^{2} - 4x +4) +11 - (4) f(x) = (x - 2)^{2} +7$