Question

rational equations: solve for x.

Answer 1

Answer:

-2 or 2 im in a rush sorry

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$x\neq -5$ and $x\neq 6$

$\frac{-11x}{x^{2}-x-30 }-\frac{8}{x-6}-\frac{x}{x+5}=0$

$\frac{-11x}{x^{2} +5x-6x-30} -\frac{8}{x-6} -\frac{x}{x+5}=0$

$\frac{-11x}{(x+5)(x-6)} -\frac{8}{x-6}-\frac{x}{x+5} =0$

$-\frac{11x+8x+40+x^{2} -6x}{(x+5)(x-6)}=0$

$-\frac{13x+40+x^{2} }{(x+5)(x-6)}=0$

$-\frac{(x+8)(x+5)}{(x+5)(x-6)}=0$

$-\frac{x+8}{x-6} =0$

$x+8=0$

$x = -8$

Please give me a brainliest answer