Question

A 4,000 mL solution of AgNO3 contains 17.00 g of solute in water. Calculate the molarity (molar concentration) of the solution.

Answer 1

Moles of AgNO3 = 17/107.86 + 14 + 16x3 = 17/169.86 = 0.1moles. Molar concentration = moles of AgNO3 /volume of solution = 0.1/4 = 0.025 moles/litre.

Answer 2

Answer: The molarity of the solution is 0.025 M.

Explanation:

Molarity is the unit of concentration. It is defined as the number of moles of solute that are present in one liter of solution.

Equation used to calculate molarity of the solution is:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Mass of silver nitrate = 17.00 g

Molar mass of silver nitrate = 170 g/mole

Volume of solution = 4000 mL

Putting values in above equation, we get:

$\text{Molarity of the solution}=\frac{17\times 1000}{170\times 4000}=0.025M$

Hence, the molarity of the solution is 0.025 M