Respuesta :
The equation of the motion is
d = 4 sin (π t)
a) When t = 0
d = 4 sin 0
d = 0
b) We take the derivative
4π cos πt = 0
t = 1/2
d = 4 sin π/2 = 4 meters
c) 1 second is required
d) The frequency is 1Hz
d = 4 sin (π t)
a) When t = 0
d = 4 sin 0
d = 0
b) We take the derivative
4π cos πt = 0
t = 1/2
d = 4 sin π/2 = 4 meters
c) 1 second is required
d) The frequency is 1Hz
Answer:
Step-by-step explanation:
The given equation is:
[tex]d=4sin({\pi}t)[/tex], where d is the displacement. (1)
(A) The position of the object at t=0 is:
[tex]d=4sin({\pi}(0))[/tex]
⇒[tex]d=4sin(0)[/tex]
⇒[tex]d=0[/tex]
The object will be at rest at t=0.
(B) In order to find the maximum displacement from the resting position, we will differentiate the given displacement.
Thus, Differentiating with respect to t, we have
[tex]d'=4cos({\pi}t)({\pi})[/tex]
⇒[tex]d'=4{\pi}cos({\pi}t)[/tex]
Now, d'=0
⇒[tex]4{\pi}cos({\pi}t)=0[/tex]
⇒[tex]cos{\pi}t=0[/tex]
⇒[tex]{\pi}t=\frac{{\pi}}{2}[/tex]
⇒[tex]t=\frac{1}{2}[/tex]
Substitute the value of t in equation (1), we get
⇒[tex]d=4sin({\pi}(\frac{1}{2}))[/tex]
⇒[tex]d=4(1)[/tex]
⇒[tex]d=4m[/tex]
Thus, the maximum displacement from its resting position will be 4m.
(C) Time required for one oscillation is equal to the period which is equal to=[tex]\frac{2\pi}{|b|}=\frac{2\pi}{\pi}=2[/tex]
thus, time required for one oscillation will be 2 seconds.
(D) Frequency is nothing but the reciprocal of period that is [tex]\frac{|b|}{2\pi}=\frac{\pi}{2\pi}=\frac{1}{2}[/tex]
Thus, the frequency will be equal to [tex]\frac{1}{2}[/tex].