Respuesta :
For the answer to the question above, I'll provide my solutions below.
x² + 4 = 0
- 4 - 4
x² = -4
x = +2i
x² - 6x + 1 = 0
x = -(-6) +/- √((-6)² - 4(1)(1))
2(1)
x = 6 +/- √(36 - 4)
2
x = 6 +/- √(32)
2
x = 6 +/- 2√(2)
2
x = 3 + √(2)
x = 3 + √(2) x = 3 - √(2)
I hope this helps.
x² + 4 = 0
- 4 - 4
x² = -4
x = +2i
x² - 6x + 1 = 0
x = -(-6) +/- √((-6)² - 4(1)(1))
2(1)
x = 6 +/- √(36 - 4)
2
x = 6 +/- √(32)
2
x = 6 +/- 2√(2)
2
x = 3 + √(2)
x = 3 + √(2) x = 3 - √(2)
I hope this helps.
Hello there.
Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your solution and tell why you chose that strategy.
x = 3 + √(2) x = 3 - √(2)
Solve each equation, if possible. Write irrational numbers in simplest radical form. Describe the strategy you used to get your solution and tell why you chose that strategy.
x = 3 + √(2) x = 3 - √(2)