Respuesta :
I have the same problem here with a slight change in the given values:
radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3....
thus the [ π radius ² thickness ] yields π (y² / 9 ) dy , y in [ 0 , 6 ] for the volume...
a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum
π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]
I hope my guide has come to your help. God bless and have a nice day ahead!
radius is 2 & height of 6 indicates the bounding line is y = 3 x---> x = y / 3....
thus the [ π radius ² thickness ] yields π (y² / 9 ) dy , y in [ 0 , 6 ] for the volume...
a Riemann sum is then : y_i = 0 + i [ 6 / n ] = 6 i / n , i = 1,2,3...n and do a right side sum
π Σ { i = 1,2,3..n } [ 36 i² / 9 n² ] [ 6 / n ]
I hope my guide has come to your help. God bless and have a nice day ahead!
The volume of the figure will be 94.2cm^3
Assuming we are solving for volume of a cone with the limited information given
Data given
- radius = 3cm
- height = 10cm
- volume of cone = ?
Volume of Cone
The formula of volume of a cone is given as
[tex]v=\frac{1}{3}\pi r^2h\\[/tex]
Let's substitute the values and solve for the volume
[tex]v = \frac{1}{3}\pi r^h\\v = \frac{1}{3}*\pi * 3^2 * 10\\v= \frac{1}{3}*3.14*9*10\\ v = 94.2cm^3[/tex]
The volume of the figure will be 94.2cm^3
Learn more on volume of a cone here;
https://brainly.com/question/13677400