Question

just need someone to check my answer

Simplify (4xy)(2x2y)(3xy)3.

24x2y3

24x6y5

216x3y3

216x6y5


Simplify (4xy)(2x^2y)(3xy)^3.

24x^2y^3

24x^6y^5

216x^3y^3

216x^6y^5

Answer 1

The correct answer is 216x⁶y⁵.

Explanation:
The first thing we do is raise the last monomial to the third power.

(4xy)(2x²y)(3xy)³
=(4xy)(2x²y)(3³x³y³)
=4xy(2x²y)(27x³y³).

Now we can multiply the first two monomials. When we multiply powers with the same base, we add the exponents:
8x³y²(27x³y³).

We multiply these last two monomials, again adding the exponents:
216x⁶y⁵.

Answer 2

Answer:  $216x^6y^5$

Step-by-step explanation:

The product law of exponents are given as :-

$a^m\times a^n=a^{m+n}$

Given expression:-$(4xy)(2x^2y)(3xy)^3$

Which can be written as

$(4xy)(2x^2y)(27x^3y^3)\\=4\cdot2\cdot27\cdot x^{1+2+3}y^{1+1+3}\\=216x^6y^5$

hence the simplifies form of the given expression is  $216x^6y^5$