Respuesta :

SO what you need to do is:
Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get |f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
   -0.4 < x - 2 < 0.4
  -0.4+2 < x < 0.4+2
  1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for

The largest δ such that if 0 < |x – 2| < δ is 0.4

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

[tex]\large {m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

[tex]y - y_1 = m ( x - x_1 )[/tex]

Let us tackle the problem.

Given:

[tex]f(x) = x + 1[/tex]

If [tex]|f(x) - 3| < 0.4[/tex] , then :

[tex]|f(x) - 3| < 0.4[/tex]

[tex]|x + 1 - 3| < 0.4[/tex]

[tex]|x -2| < 0.4[/tex]

Since the absolute value of a function is always positive, then:

[tex]0 < |x -2| < 0.4[/tex]

From the relationship above, then the largest δ such that :

[tex]0 < |x - 2| < \delta[/tex]

→ δ = 0.4

Learn more

  • Infinite Number of Solutions : https://brainly.com/question/5450548
  • System of Equations : https://brainly.com/question/1995493
  • System of Linear equations : https://brainly.com/question/3291576

Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

Ver imagen johanrusli
ACCESS MORE
EDU ACCESS