Question

When eight is added to three times a number the result is sixty-eight. Write and solve an algebraic equation. Show all work.

Answer 1

Answer:

3n + 8 = 68

         n = 20

Step-by-step explanation:

We know that certain words mean certain operations. For example, when you hear "multiply by" or "times" you would think of multiplication! Same goes here.

It is saying that 8 is being added to 3 times a number. Let's just assign n to the "number." So 3 times n is the same thing as 3n. Now we just add 8 to it.

              3n + 8.

However, we are not quite done yet. The problem says that the result is sixty-eight, we know that the "result" of something is basically the solution.

Thus, the equation is:

3n + 8 =68

To solve this, we need to isolate the variable "n"

First, we subtract 8 on both sides leaving us with...

3n = 60

Next, we divided both sides by 3

And the answer is n = 20

Hope this is helpful! :)

Answer 2

$▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let the number be y, now the above statement can be expressed as :

• $3y + 8 = 68$

• $3y = 68 - 8$

• $3y = 60$

• $y = 60 \div 3$

• $y = 20$

the required number is 20