Question

Un avión vuela horizontalmente con una velocidad de 800 km/h y deja caer
un proyectil desde una altura de 500 respecto al suelo. a) ¿Cuánto tiempo
transcurre antes de que el proyectil se impacte en el suelo?; b) ¿Qué distancia
horizontal recorre el proyectil después de iniciar su caída?

Answer 1

The projectiles launch allows to find the results for the questions of the launch of the bomb are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

Projectile launching is an application of kinematics where the acceleration on the x-axis is zero and the acceleration on the y-axis is gravity acceleration.

a) Let's find the time until we reach the ground.

The initial vertical velocity is zero, the initial height is I = 500 m, when reaching the ground its height y = 0.

        $y = y_o + v_o_y - \frac{1}{2} g t^2$  

        0 = y₀ + 0 - ½ g t²

        t = $\sqrt{\frac{2y_o}{g}$  

        t = $\sqrt{\frac{2 \ 500}{9.8} }$  

        t = 10.1 s

b) We look for the horizontal distance traveled.

Let's reduce to the international measurement system (SI).

       v = 800 km / h ($\frac{1000m}{1km}$) ($\frac{1h}{3600s}$) = 222.22 m / s

       x = vₓ t

       x = 22.22 10.1

       x = 2.24 10³ m

In conclusion, using the projectile launch relationships, we can find the results for the questions that are:

     a) The fall time is: t = 10.1 s

     b) The distance traveled is: x = 2.24 10³ m

Learn more here: brainly.com/question/6287497