To balance a redox reeaction equation, the number of electrons lost must be equal to the number of electrons gained. The balanced equation is; 2IO₃⁻ (aq) + 12OH⁻(aq) + 6SO3^2⁻ (aq) → 2 I⁻ (aq) + 12OH⁻(aq) + 6 SO4^2-(aq)
In a redox reaction, electrons are lost or gained. The number of electrons lost by the reducing agent in a reaction must be equal to the number of electrons gained by the oxidizing agent in a reaction. All these are captured in a balanced redox reaction equation for the reaction
The reduction half equation, is written follows;
2IO₃⁻ (aq) + 12H⁺ (aq) + 12OH⁻ + 12e⁻→ I⁻ (aq) + 6H₂O (l) + 12OH⁻
The oxidation half equation is written as follows;
6SO3^2⁻ (aq) + 6H2O(l) -----> 6 SO4^2-(aq) + 12e⁻ + 12H^+
The balanced equation for the reduction of iodate by hydrogen sulfite ions to give iodide and sulfate in basic aqueous solution is;
2IO₃⁻ (aq) + 12OH⁻(aq) + 6SO3^2⁻ (aq) → 2 I⁻ (aq) + 12OH⁻(aq) + 6 SO4^2-(aq)
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