Answer:
76 and 77 are the locker numbers.
Step-by-step explanation:
Let the number be x and (x + 1)
The sum of two consecutively number is 153
Now,
x + (x + 1) = 153
x + x + 1 = 153
2x + 1 = 153
Now, subtract 1 from both side we get,
2x + 1 - 1 = 153 - 1
2x = 152
Now, divide by 2 from both side we get,
2x/2 = 152/2
x = 76
Here, The value of x is 76
Now, the first number = x = 76 and the Second number = (x + 1) = 76 + 1 = 77
Thus, 76 and 77 are the locker numbers.
x + (x + 1) = 153
76 + (76 + 1) = 153
153 = 153
L.H.S = R.H.S
Hence Proved!
-TheUnknownScientist 72