Respuesta :
Answer:
n(n - m)
Step-by-step explanation:
n² - mn ← factor out n from each term
= n(n - m)
Answer:
n(n-m)
Step-by-step explanation:
We are given the quadratic expression:-
[tex] \displaystyle \large{ {n}^{2} - mn}[/tex]
To factor this expression, do you notice that there are two n's in the expression? Yes, since in the expression, the whole terms have n-term; what we are going to do is to common factor n out!
So how do we do that? Simple, just pull n out.
[tex] \displaystyle \large{n( {n} - m)}[/tex]
From above, you might be wondering how does it turn out like this. Do not worry, I've got you!
When we pull n out of the expression, we just divide the expression by n.
Don't get it? Let me show you!
Step 1 - Form the expression:
[tex] \displaystyle \large{ {n}^{2} - mn}[/tex]
Step 2 - Pull n out and bracket the expression.
[tex] \displaystyle \large{n( {n}^{2} - mn)}[/tex]
Step 3 - Divide the expression by n.
[tex] \displaystyle \large{n( \frac{ {n}^{2} - mn}{n})} \\ \displaystyle \large{n( n - m)}[/tex]
Still not get it? Well, let's demonstrate another method.
Let's say we have the expression again!
[tex] \displaystyle \large{ {n}^{2} - mn}[/tex]
Since n^2 comes from n•n.
[tex] \displaystyle \large{ n \cdot n - mn}[/tex]
Bracket the expression:
[tex] \displaystyle \large{ (n \cdot n - mn)}[/tex]
Now let's imagine that these two brackets are the doors.
m-term: There are so many of you in this bracket house! If this keeps continuing, this bracket house might be collapsed!
3 n-terms were shocked! They had to find the ways to protect their bracket house, the legacy that their cases parents gave.
But then the 2 n-terms did an unexpected! They decided to help them by going outside of the bracket house and stand there!
m-term: Why there is only one n-term outside when two of them left?
another n-term: Well, the another n-term finds food for themselves and the another one there guards our bracket house.
The End!
As we get:
[tex] \displaystyle \large{n ( n - m)}[/tex]
Not clearing all your doubts? Let me know or ask your doubts under my comment!