The number of mole of the gas in the container is 7.58×10¯⁵ mole
From the question given above, the following data were obtained:
Temperature (T) = 250 K
Volume (V) = 1.5 L
Pressure (P) = 105 Pa = 105 / 1000 = 0.105 KPa
Gas constant (R) = 8.314 L.KPa/Kmol
The number of mole of the gas in the container can be obtained as by using the ideal gas equation as illustrated below:
0.105 × 1.5 = n × 8.314 × 250
0.1575 = n × 2078.5
Divide both side by 2078.5
n = 0.1575 / 2078.5
Therefore, the number of mole of the gas in the container is 7.58×10¯⁵ mole
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