According to the distribution, we have that:
The probability distribution for the prizes is given by:
[tex]P(X = 200,000) = 0.00000000764[/tex]
[tex]P(X = 10,000) = 0.00000019[/tex]
[tex]P(X = 100) = 0.000001787[/tex]
[tex]P(X = 7) = 0.004859191[/tex]
[tex]P(X = 4) = 0.006351519[/tex]
[tex]P(X = 3) = 0.01781606[/tex]
[tex]P(X = 0) = 0.97082745836[/tex]
The expected cash price is given by the sum of each outcome multiplied by it's probability, thus:
[tex]E(X) = 0.00000000764(200000) + 0.00000019(10000) + 0.000001787(100) + 0.004859191(7) + 0.006351519(4) + 0.01781606(3) + 0.97082745836(0) = 0.1165[/tex]
The expected cash price is of $0.1165, which means that if a person plays the game many times, on average, the cash price earned would be of $0.1165 per game.
The profit is the expected cash price subtracted by the cost, thus:
[tex]P = 0.1165 - 1 = -0.8835[/tex]
The expected profit from one ticket is of -$0.8835.
A similar problem is given at https://brainly.com/question/24855677