Question

Which system of equations can be used to solve the following problem?
Each child ticket for a ride costs 2$ , while each adult ticket costs 6$ . if the ride collected a total of 148$ , and 38 tickets were sold , how many of each type of ticket were sold? let c be the number of child tickets and a be the number of adult tickets.

A. 2a+6c=38
a+c=148

B. 2c+6a=38
a+c=148

C. 2c+6a=148
a+c=38

D. 6c+2a=148
c+a=38

Answer 1

I hope this helps you

Answer 2

Hi :)
The answer for your problem is C

Why?
Because content of your task was sayid Each child ticket for a ride costs 2$" and we know that child is called "c" so
2c
now time for adults."while each adult ticket costs 6$"  and adults is called a so :
6a

2c+6a ="if the ride collected a total of 148$"
so
2c+6a=148
And if we summaries all the tickets we receive 38

So the final form 
2c+6a=148
a+c=38