Question

Between 9 PM and 6:36 AM, the water level in a swimming pool decreased by 4/25 Assuming that the water level decreased at a constant rate, how much did the water level drop each hour? pls help ​

Answer 1

Answer:

$\frac{1}{60}$per hour

Step-by-step explanation:

First, you need to find the total amount of time that the pool decreased by 4/25. Since there are 9 hours and 36 minutes between 9 PM and 6:36 AM, this time is 9 hours and 36 minutes. Next, convert this time into hours, which gives the time as 6 and 36/60 hours, or 9 $\frac{3}{5}$ hours.

For this problem you need to find the rate at which the water decreases. To do this you can use the equation $rate=\frac{change}{time}$. Substitute in the given change of 4/25 and time of 6.6 and you get the equation $rate=\frac{4/25}{9\frac{3}{5} }$. Solving this by changing the fractions to improper fractions and doing fraction division gives $rate=\frac{1}{60}$.

Answer 2

Answer:

• 1/60 per hour

Step-by-step explanation:

The time between 9 PM and 6:36 AM:

• 3 + 6 36/60 = 9 3/5 = 48/5 hours

The level drop is:

• 4/25

The rate of level drop each hour:

• 4/25 : 48/5 =
• 4/25 * 5/48 =
• 1/60