Respuesta :
Maximizing profit, is a way of getting the highest possible profit, from a function.
The bakery should make 45 loaves of A and 0 loaves of B, to maximize profit
To do this, we make use of the following representations.
x represents source A, and y represents source B
So, we have:
Constraint 1:
A uses 5 pounds, and B uses 2 pounds of oats.
Available: 180
The above condition is represented as;
[tex]\mathbf{5x + 2y \le 180}[/tex]
Constraint 2:
A and B use 3 pounds of flour each.
Available: 135
The above condition is represented as;
[tex]\mathbf{3x + 3y \le 135}[/tex]
Objective function
A yields $40, while B yields $30
So, the objective function is:
[tex]\mathbf{Maximize\ Z = 40x + 30y}[/tex]
So, we have:
[tex]\mathbf{Maximize\ Z = 40x + 30y}[/tex]
Subject to
[tex]\mathbf{5x + 2y \le 180}[/tex]
[tex]\mathbf{3x + 3y \le 135}[/tex]
[tex]\mathbf{x,y \ge 0}[/tex]
See attachment for the graph of the subjects
From the graph, we have the corner points to be:
[tex]\mathbf{(x,y) = \{(0,45),(30,15),(45,0)\}}[/tex]
Substitute these values in the objective function
[tex]\mathbf{Z = 40(0) +30(45) = 1350}[/tex]
[tex]\mathbf{Z = 40(30) +30(15) = 1650}[/tex]
[tex]\mathbf{Z = 40(45) +30(0) = 1800}[/tex]
The maximum value of Z is at: (45,0)
This means that: the bakery should make 45 loaves of A and 0 loaves of B, to maximize profit
Read more about maximizing functions at:
https://brainly.com/question/14728529
![Ver imagen MrRoyal](https://us-static.z-dn.net/files/d5b/4e453ff067819bc7216b91daae1ad2d8.png)