Using the principle of probability, the probability of the events in the question are :
To obtain the sample space, take the following steps :
Coin toss = ( H, T)
Die throw = (1, 2, 3, 4, 5, 6)
First experiment :
If H : roll a die once :
If T ; toss coin twice :
A.) The ten elements of the sample space :
B.)
Event A = exactly one head occurs
P(A) = required outcome / Total possible outcomes
P(A) = 8/10 = 4/5
C.)
Event B = atleast two tails or a number greater than 4
atleast 2 tails or number greater than 4 = 5
P(B) = 5/10 = 1/2
Therefore, the probability of event B is 0.5.
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