Consider the sequence whose first five terms are shown below.
8, 6, 4, 2, 0

Which function, with the domain of n = {1, 2, 3, 4, 5} defines this sequence?

A. f (n) = -2n + 10

B. f (n) = n -2

C. f (n) = -10n + 2

D. f (n) = -n + 9

Respuesta :

Answer:

f (n) = -2n + 10

Step-by-step explanation:

I completed the sample work

The required function is [tex]f(n)=-2n+10[/tex]. So, the correct option is A.

Given:

  • The first five terms are [tex]8, 6, 4, 2, 0[/tex].
  • The domain of the function is [tex]n=\{1,2,3,4,5\}[/tex].

To find:

The function that defines the given sequence.

Explanation:

The given sequence is an arithmetic sequence because the difference between the consecutive terms is constant.

First-term [tex]= 8[/tex]

The common difference is:

[tex]6-8=-2[/tex]

The function for [tex]n[/tex]th term is:

[tex]f(n)=a+(n-1)d[/tex]

Where [tex]a[/tex] is the first term and [tex]d[/tex] is a common difference.

Substitute [tex]a=,d=-2[/tex].

[tex]f(n)=8+(n-1)(-2)[/tex]

[tex]f(n)=8-2n+2[/tex]

[tex]f(n)=-2n+10[/tex]

Therefore, the correct option is A.

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