Question

A car is initially sliding backwards down a hill at -25 km/h. The driver guns the car. By the time the car's velocity is +35 km/h, it is +3.2 m from its starting point. Assuming the car was uniformly accelerated, find the acceleration. I NEED THIS WITH STEPS

Answer 1

Answer:

7.2375m/s^2

Explanation:

initial velocity=-25 km/h=-6.94m/s

final velocity=35 km/h=9.72m.s

distance=3.2m

v^2=u^2+2as

9.72^2=-6.94^2+2a*3.2

94.48=48.16+6.4a

(94.48-48.16)/6.4=a

7.2375m/s^2