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Write the quadratic equation that has roots -1-√2/3 and -1+√2/3 , if it's coefficient with x^2 is equal to
a.) -3/5
b.) √3 / 3

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Answer:

  a) -3/5x² -2/5x +1/15 = 0

  b) √3/3x² +2√3/9x -√3/27 = 0

Step-by-step explanation:

The quadratic equation of interest is of the form ...

  (leading coefficient)(x^2 -(sum of roots)x +(product of roots)) = 0

The sum of the given roots is ...

  (-1 +√2)/3 +(-1 -√2)/3 = -2/3

The product of the given roots is ...

  (-1 +√2)/3×(-1 -√2)/3 = ((-1)² -(√2)²)/3² = -1/9

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a) The quadratic is ...

  (-3/5)(x² +2/3x -1/9) = -3/5x² -2/5x +1/15 = 0

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b) The quadratic is ...

  (√3/3)(x² +2/3x -1/9) = √3/3x² +2√3/9x -√3/27 = 0

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