Question

Can someone help me with this
$f=\frac{e1}{8.6R1C1}$

calculate R1 for a frequency of 1 KHz at 10 volts input (e1) free capacitor (example 10micro farad)

Answer 1

Answer:

116.2791 V/Hz*F

Step-by-step explanation:

Rearranging for R1:

$8.6*f*R1*C1=e1$

$R1=\frac{e1}{8.6*f*C1}$

Plugging in values:

e1=10V

f=$1*10^{3}$ Hz

C1=$10*10^{-6}$ F

$R1=\frac{10V}{8.6*(1*10^3Hz)(10*10^{-6} F)}=\frac{10V}{0.086Hz*F}=116.2791 V/Hz*F$