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Answer:

[tex](-20,\, 13)[/tex] would be in the second quadrant of the cartesian plane.

[tex](-12,\, -8)[/tex] would be in the third quadrant of the cartesian plane.

Step-by-step explanation:

The horizontal and vertical axes of the cartesian plane divides the plane into four quadrants. By convention, these quadrants are numbered counterclockwise starting from the quadrant on the top right:

[tex]\begin{array}{c|c}\text{Second Quadrant} & \text{First Quadrant} \\ \cline{1-2}\\[-1em] \text{Third Quadrant} & \text{Fourth Quadrant}\end{array}[/tex].

  • Top-left: first quadrant.
  • Top-right: second quadrant.
  • Bottom-left: third quadrant.
  • Bottom-right: fourth quadrant.
  • Points on either axes (where at least one of the coordinates is [tex]0[/tex]) are not in any of the four quadrants.

The [tex]x[/tex]-coordinate of the first point, [tex](-20,\, 13)[/tex], is [tex]x = -20[/tex], which is negative. Thus, this point would be to the left of the vertical axis.

Since the [tex]y[/tex]-coordinate of this point, [tex]y = 13[/tex], is positive, this point would be above the horizontal axis.

Thus, the point [tex](-20,\, 13)[/tex] would be in the quadrant on the top-left corner of the cartesian plane. Therefore, this point would be in the second quadrant of the plane.

The second point [tex](-12,\, -8)[/tex] would also be to the left of the vertical axis since the [tex]x[/tex]-coordinate of this point, [tex]x = -12[/tex], is negative.

This point would be below the horizontal axis since the [tex]y[/tex]-coordinate of this point [tex]y = -8[/tex] is negative.

Thus, the point [tex](-12,\, -8)[/tex] would be in the quadrant on the lower-left corner of the cartesian plane. This point would be thus be in the third quadrant of the plane.

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