Question

Help me with this parallelogram please :)

Answer 1

Parallel sides of parallelogram are equal in length

$\\ \sf\longmapsto AD=BC$

$\\ \sf\longmapsto 6x+14=9x-4$

$\\ \sf\longmapsto 9x-6x=14+4$

$\\ \sf\longmapsto 3x=18$

$\\ \sf\longmapsto x=6$

AD=6x+14=6(6)+14=36+14=50

Option D

Answer 2

The opposite sides of parallelogram are equal in length, so we can infer that :

• BC = AD

now, let's solve for value of x :

• $9x - 4 = 6x + 14$

• $9x - 6x = 14 + 4$

• $3x = 18$

• $x = 18 \div 3$

• $x = 6$

we have to find the measure of AD,

• $6x + 14$

Plugging the value of x as 6 :

• $(6 \times 6) + 14$

• $36 + 14$

• $50$

The Correct option is D. 50