Chase has $640 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
He buys a new bicycle for $328.37.
He buys 3 bicycle reflectors for $12.99 each and a pair of bike gloves for $26.62.
He plans to spend some or all of the money he has left to buy new biking outfits for $45.63 each.

Which inequality can be used to determine
o
o, the maximum number of outfits Chase can purchase while staying within his budget?

Respuesta :

328.37 + 12.99(3) + 26.62 + 45.63x = 640

Answer:

640≥393.96+45.63o

Step-by-step explanation:

\text{We know:}

We know:

\color{blue}{\text{cost of bike \& gear}}=

cost of bike & gear=

\,\,\color{blue}{\$393.96}

$393.96

\color{red}{\text{cost per outfit}}=

cost per outfit=

\,\,\color{red}{\$45.63}

$45.63

\color{purple}{\text{budget}}=

budget=

\,\,\color{purple}{\$640}

$640

\text{\# of outfits}=

# of outfits=

\,\,o

o

Some or all means he can also spend less than $640, so we will use the \leq≤ ("less than or equal to") symbol:

\color{red}{\text{cost per outfit}}\cdot\text{\# of outfits}+\color{blue}{\text{cost of bike \& gear}}\leq\color{purple}{\text{budget}}

cost per outfit⋅# of outfits+cost of bike & gear≤budget

\color{red}{45.63}o+\color{blue}{393.96}\leq

45.63o+393.96≤

\,\,\color{purple}{640}

640

\star⋆ Inequality #1

\text{or, by the commutative property of addition,}

or, by the commutative property of addition,

\color{blue}{393.96}+\color{red}{45.63}o\leq

393.96+45.63o≤

\,\,\color{purple}{640}

640

\star⋆ Inequality #2

We could also switch the two sides of the inequality, but we have to be careful which symbol we use. Some or all means his budget should always be greater than or equal to the total cost, including the bike & gear plus all the outfits.

\color{purple}{640}\geq

640≥

\,\,\color{red}{45.63}o+\color{blue}{393.96}

45.63o+393.96

\star⋆ Inequality #3

\text{or}

or

\color{purple}{640}\geq

640≥

\,\,\color{blue}{393.96}+\color{red}{45.63}o

393.96+45.63o

\star⋆ Inequality #4

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