Question

Bob paid $1,210 for 5 tables and 7 chairs for his company. Each table costs 3 times as much as each chair. If Ann bought 8 such tables and 4 such chairs, how much money would she have to pay

Answer 1

Bob: 5t + 7c = 1210
t = 3c
Use substitution
5(3c) + 7c = 1210
15c + 7c = 1210
22c = 55
Chairs cost $55
5t + 7(55) = 1210
5t + 385 = 1210
5t = 825, t = 165
Tables cost $165
Ann = 8(165) + 4(55) = 1320 + 220

Solution: $1540

Answer 2

Answer:

Step-by-step explanation:

Let x be the price of tables

Let y be the price of chairs

5x + 7y = 1210

x = 3y

5(3y) + 7y = 1210

         22y = 1210

             y = $55

 x = 3(55) = $165

8(165) + 4(55) = $1540