Question

A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width of the picture frame, and let l represent the length. Which system of equations can be used to find the dimensions of the picture frame?

2l+2w=40
l=2+1/2w

2l+2w=40
l=1/2w-2

lw=40
l=1/2w-2

lw=40
l=2+1/2w

Answer 1

The answer is
2l+2w=40
l=2+1/2w

The perimeter of a rectangle is:
P = 2l + 2w
A picture frame has a perimeter of 40 inches:
P = 40 in

P = 2l + 2w = 40 in
2l + 2w = 40

Its length is 2 inches greater than one-half its width:
l = 2 + 1/2w

The system of equations is:
2l + 2w = 40
l = 2 + 1/2w

Answer 2

Answer: long story short it's (A)

Step-by-step explanation: