Question

Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.

x − 2y = −12
y = one halfx
y = one halfx + 6
y = one halfx + 9

Answer 1

Answer:

$x-2y=-12$

Step-by-step explanation:

We have been given an equation of a line in point-slope form. We are asked to write our given equation in standard form.

$y-3=\frac{1}{2} (x+6)$

Since we know that standard form of equation is:  where, a, b and c are constants.

Let us multiply both sides of our given equation by 2.

$(y-3)*2=2*\frac{1}{2} (x+6)\\2y-6=x+6$

Let us add 6 to both sides of our equation.

$2y-6+6=x+6+6$

$2y=x+12$

Let us subtract x from both sides of our equation.

$2y-x=x-x+12\\2y-x=12$

Multiply both sides of our equation by -1.

$-2y+x=-12$

Rearranging our equation we will get,

$x-2y=-12$

Therefore, the standard form of our given equation is $x-2y=-12$

and option A is the correct choice.